4s^2+rs+5r^2=0

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Solution for 4s^2+rs+5r^2=0 equation:


Simplifying
4s2 + rs + 5r2 = 0

Reorder the terms:
rs + 5r2 + 4s2 = 0

Solving
rs + 5r2 + 4s2 = 0

Solving for variable 'r'.

Begin completing the square.  Divide all terms by
5 the coefficient of the squared term: 

Divide each side by '5'.
0.2rs + r2 + 0.8s2 = 0

Move the constant term to the right:

Add '-0.8s2' to each side of the equation.
0.2rs + r2 + 0.8s2 + -0.8s2 = 0 + -0.8s2

Combine like terms: 0.8s2 + -0.8s2 = 0.0
0.2rs + r2 + 0.0 = 0 + -0.8s2
0.2rs + r2 = 0 + -0.8s2
Remove the zero:
0.2rs + r2 = -0.8s2

The r term is rs.  Take half its coefficient (0.5s).
Square it (0.25s2) and add it to both sides.

Add '0.25s2' to each side of the equation.
0.2rs + r2 + 0.25s2 = -0.8s2 + 0.25s2

Combine like terms: -0.8s2 + 0.25s2 = -0.55s2
0.2rs + r2 + 0.25s2 = -0.55s2

Factor a perfect square on the left side:
(r + 0.5s)(r + 0.5s) = -0.55s2

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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